Subject: World size
From: Jari P Saukkonen (jsaukkon@cs.Helsinki.FI)
Date: Wed Dec 01 1999 - 00:04:39 EET
There was some talk about this long time ago, perhaps during Majik4 times. Could someone tell me if we came to a good conclusion back then? I didn't find any from the archives :( So, how much land do we need? The new "worldtree" will have a maximum of 65536 x 65536 leaves (containers for objects and map) and each leaf will cover 32m x 32m (or 64) area or something [not decided, good size depends on the amount of objects]. The maximum size for the world would be 2097km x 2097km (using 32m resolution). The resulting worldtree's size would be size = leaves_x * leaves_y * 5 bytes which would make around 20 gigabytes for theoretical maximum size. That amount does NOT count any object or terrain data -- it's just the data structure holding the world together. Also, if the terrain has not been modified in any way and there aren't any objects in a leaf's area it doesn't need to be stored anywhere. In contrast, if there has been lots of changes in the terrain a leaf will take much more space (up to few kilobytes). Harum proposed a size of 131km x 131km (4096x4096 nodes, 32m resolution). That would use ~84 megabytes (+ terrain + objects) for the world. This sounds reasonable to me, any objections? +++ dazzt --- | Jari Saukkonen + jari.saukkonen@cs.helsinki.fi : coral -. | programming music graphics | dolphin : | art keyboards web | nah-kolor | +------------------------------------------------+-----------' | Babylon5-inspired 'shadow function' 0 <= t <= 4*pi/3 : x(t) = (sin 8t)^2 * (5 + 3sin 8t) cos (t/2 + (sin 8t)^2) . y(t) = +-(sin 8t)^2 * (5 + 3cos 8t) sin (t/2 + (sin 8t)^2)
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